x^2+4x-528=0

Solution for x^2+4x-528=0 equation:

x^2+4x-528=0

a = 1; b = 4; c = -528;
Δ = b2-4ac
Δ = 42-4·1·(-528)
Δ = 2128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2128}=\sqrt{16*133}=\sqrt{16}*\sqrt{133}=4\sqrt{133}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{133}}{2*1}=\frac{-4-4\sqrt{133}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{133}}{2*1}=\frac{-4+4\sqrt{133}}{2}
$